London, England (SportsNetwork.com) - Six-time champion Roger Federer was an
easy round-robin winner Thursday at the season-ending $6 million ATP World
The sixth-seeded Swiss great cruised past eighth-seeded Richard Gasquet 6-4,
6-3 in 81 minutes at London's O2 Arena. Federer popped six aces, compared to
zero for Gasquet, and the former world No. 1 broke his opponent four times,
compared to only one break for the Frenchman.
Thursday's other round-robin affair will pit second-seeded Novak Djokovic
against fourth seed Juan Martin del Potro. The former world No. 1 and two-time
Tour Finals champion Djokovic beat Federer in last year's finale in London.
The former U.S. Open champion del Potro was the runner-up at this prestigious
eight-player event back in 2009.
This week's four-player "Group A" features U.S. and French Open champion
Rafael Nadal (2-0), Roland Garros runner-up David Ferrer (0-2), former
Wimbledon finalist Tomas Berdych (1-1), and Stan Wawrinka (1-1).
"Group B" is comprised of the Australian Open titlist Djokovic
(1-0), del Potro (1-1), the 17-time Grand Slam winner Federer (1-1), and
Gasquet (0-2). Djokovic has won his last 18 matches overall on tour,
including a title last week at the Paris Masters.
The sizzling Djokovic and Federer are the only former Tour Finals champions
in this week's field. Nadal (2010), Ferrer (2007) and del Potro are former
Round-robin play will be staged through Saturday, with the semifinals
on Sunday, and the final on Monday. The top-two players from each group will
qualify for the semis.
An undefeated champion this week would earn $1.923 million.
The Sports Network